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Question 40.42: From Fig. 40-13, calculate approximately the energy differen......

From Fig. 40-13, calculate approximately the energy difference E_L – E_M for molybdenum. Compare it with the value that may be obtained from Fig. 40-15.

1360823-Figure 40.13
1360823-Figure 40.15
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Using hc = 1240 eV·nm = 1240 keV·pm, the energy difference E_L – E_M for the x-ray atomic energy levels of molybdenum is

\Delta E=E_L-E_M=\frac{h c}{\lambda_L}-\frac{h c}{\lambda_M}=\frac{1240 \,keV \cdot pm }{63.0 \, pm }-\frac{1240 \,keV \cdot pm }{71.0 \,pm }=2.2 \,keV .

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