A R-410A heat pump cycle shown in Fig. P4.123 has a R-410A flow rate of 0.1 lbm/s with 4 Btu/s into the compressor. The following data are given
| State | 1 | 2 | 3 | 4 | 5 | 6 |
| P psia | 410 | 405 | 400 | 62 | 60 | 58 |
| T F | 220 | 200 | 110 | 10 | 14 | |
| h Btu/lbm | 154 | 150 | 56 | _ | 120 | 122 |
Calculate the heat transfer from the compressor, the heat transfer from the R-410A in the condenser and the heat transfer to the R-410A in the evaporator.
CV: Compressor
\dot{ Q }_{ COMP }=\dot{ m }\left( h _{1}- h _{6}\right)+\dot{ W }_{ COMP }=0.1(154-122)-4.0=- 0 . 8 Btu / s
CV: Condenser
\dot{ Q }_{ COND }=\dot{ m }\left( h _{3}- h _{2}\right)=0.1 lbm / s (56-150) Btu / lbm =-9.4 Btu / s
C.V. Valve:
h _{4}= h _{3}=56 Btu / lbm
CV: Evaporator
\dot{ Q }_{ EVAP }=\dot{ m }\left( h _{5^{-}} h _{4}\right)=0.1 lbm / s (120-56) Btu / lbm = 6 . 4 Btu / s
