Calculate the ratio of starting torque to full-load torque of a 3-phase induction motor having short-circuit current 4 times the full-load current with a full-load slip of 3%.
Question 10.1: Calculate the ratio of starting torque to full-load torque o...
Hence, I_{sc } = 4 I_{fl}; S_{f} = 3\% = 0.03
Ratio of starting to full-load torque, \frac{T_{st}}{T_{fl}} = \left\lgroup\frac{I_{sc}}{ I_{fl}}\right\rgroup^{2} \times S_{f} = \left(4\right)^{2} \times 0.03 = \mathbf{0.48}
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