Question 10.2: Determine the ratio of starting current to full-load current...

Here, I_{sc} = 5  I_{fl }; x= 70\% = 0.7; S_{f} = 4\% = 0.04

Starting current, I_{st} = x I_{sc } = 0.7 \times 5 \times I_{fl} = 3.5 I_{fl}

or \frac{I_{st}}{I_{fl}} = \mathbf{3.5}

Starting torque, T_{st} = T_{st} = \left\lgroup\frac{I_{st}}{I_{fl}}\right\rgroup^{2} \times S_{f} \times T_{fl}

or \frac{T_{st}}{ T_{fl}} = \left(3.5\right)^{2} \times 0.04 = 0.49 = \mathbf{49 \%}