Question 7.117: A 0.2 m^3 initially empty container is filled with water fro...

C.V. The container volume and any valve out to line.

Continuity Eq.4.15:          m _{2}- m _{1}= m _{2}= m _{ i }

Energy Eq.4.16:                m _{2} u _{2}- m _{1} u _{1}= m _{2} u _{2}={ }_{1} Q _{2}-{ }_{1} W _{2}+ m _{ i } h _{ i }= m _{ i } h _{ i }

Entropy Eq.7.12:              m _{2} s _{2}- m _{1} s _{1}= m _{2} s _{2}=\int d Q / T +{ }_{1} S _{2  gen }+ m _{ i } s _{ i }

Process:    Adiabatic  { }_{1} Q _{2}=0 ,  Rigid  { }_{1} W _{2}=0    Flow stops      P _{2}= P _{\text {line }}

State i:    h _{ i }=2855.37   kJ / kg ; \quad s _{ i }=7.0592   kJ / kg K

State 2:    500   kPa , \quad u _{2}= h _{ i }=2855.37   kJ / kg    => Table B.1.3

From the entropy equation

………………………………………..

Eq.4.15 : 1=\frac{\dot{m}_{1}}{\dot{m}_{3}}+\frac{\dot{m}_{2}}{\dot{m}_{3}}

Eq.4.16 : 0=\frac{\dot{m}_{1}}{\dot{m}_{3}} h_{1}+\frac{\dot{m}_{2}}{\dot{m}_{3}} h_{2}-h_{3}+\dot{Q} / \dot{m}_{3}

Eq.7.12 : \left(m_{2} s_{2}-m_{1} s_{1}\right)_{ c . v .}=\sum m_{i} s_{i}-\sum m_{e} s_{e}+\int_{0}^{t} \sum_{ c.s. } \frac{\dot{Q}_{ c.v. }}{T} d t+{ }_{1} S_{2 gen }