The exit velocity of a nozzle is 1500 ft/s. If \eta_{\text {nozzle }}=0.88 what is the ideal exit velocity?
Question 7.228E: The exit velocity of a nozzle is 1500 ft/s. If ηnozzle = 0.8...
The nozzle efficiency is given by Eq. 7.30 and since we have the actual exit velocity we get
V _{ e s }^{2}= V _{ a c }^{2} / \eta_{\text {nozzle }} \RightarrowV _{ e s }= V _{ ac } / \sqrt{\eta_{\text {nozzle }}}=1500( ft / s ) / \sqrt{0.88}= 1 5 9 9 ft / s
………………………………..
Eq.7.30 : \eta_{ nozz }=\frac{ V _{e}^{2} / 2}{ V _{e s}^{2} / 2}
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