Question 7.65: The beam supports a vertical shear of V = 7 kip. Determine t...

The beam supports a vertical shear of V = 7 kip. Determine the resultant force developed in segment AB of the beam.

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Section Properties:

I_{N A}=\frac{1}{12}(1)\left(5^{3}\right)+\frac{1}{12}(10)\left(0.5^{3}\right)=10.52083  \mathrm{in}^{4}

 

Q=\bar{y}^{\prime} A^{\prime}=(0.5 y+1.25)(2.5-y)(0.5) \\ \quad=1.5625-0.25 y^{2}

 

Shear Flow:

q=\frac{V Q}{I} =\frac{7\left(10^{3}\right)\left(1.5625-0.25 y^{2}\right)}{10.52083} \\ \quad=\left\{1039.60-166.34 y^{2}\right\}  \mathrm{lb/in}.

 

Resultant Shear Force: For web A B

V_{A B} =\int_{0.25  \mathrm{in} .}^{2.5  \mathrm{in} .} q d y

 

=\int_{0.25  \mathrm{in} .}^{2.5  \mathrm{in.}}\left(1039.60-166.34 y^{2}\right) d y

 

=1474  \mathrm{lb}=1.47  \mathrm{kip}
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