A)
\begin{gathered}\text{Velocity} =\frac{\text { Distance }}{\text { Time }}\\\text{Velocity} =\left(\frac{10 \text { furlong }}{2 \mathrm{~min}}\right)\left(\frac{1 \text { mile }}{8 \text { furlongs }}\right)\left(\frac{1 \mathrm{~min}}{60 \mathrm{~s}}\right)\left(\frac{5280 \mathrm{~ft}}{1 \mathrm{~mile}}\right)\left(\frac{1 \mathrm{~m}}{3.2808 \mathrm{~ft}}\right)=\mathbf{1 6 . 6 7} \frac{\mathbf{m}}{\mathbf{s}}\\\text{Velocity}=\left(\frac{10 \text { furlong }}{2 \text { min }}\right)\left(\frac{1 \text { mile }}{8 \text { furlongs }}\right)\left(\frac{60 \mathrm{~min}}{1 \text { hour }}\right)=\bf 37 \frac{\bf\text { miles }}{\bf\text { hour }}\end{gathered}
B) (20\,\text{fathoms })\left(\frac{6 \mathrm{\,ft}}{1 \text { fathom }}\right)\left(\frac{1 \mathrm{~m}}{3.2808 \mathrm{\,ft}}\right)=\bf 36.56 \,meters
C) Work = Force × Distance = Mass × Acceleration × Distance
\begin{gathered}\text{Work} =\left(100~ \mathrm{lb}_{\mathrm{m}}\right)\left(32.2 \frac{\mathrm{ft}}{\mathrm{sec}^{2}}\right)(500~ \rm fathoms )\left(\frac{6~ \mathrm{ft}}{1~ \mathrm{fathom}}\right)\left(\frac{1~ \mathrm{lb}_{\mathrm{f}}}{32.2 \frac{\mathrm{ft} \,\mathrm{l} \mathrm{b}_{\mathrm{m}}}{\mathrm{sec}^{2}}}\right)\\ =300000 \,\mathrm{ft}\,\mathrm{lb}_{\mathrm{f}}\\\text{Work}=\left(300000 \,\mathrm{ft}\, \mathrm{lb}_{\mathrm{f}}\right)\left(\frac{1.3558 \mathrm{~J}}{1 \,\mathrm{ft} \,\mathrm{lb}_{\mathrm{f}}}\right)=406,740 \mathrm{~J} \sim \bf 407,000 \,Joules \end{gathered}