Solve Prob. 8–77 if the bar has a circular cross section of 30-mm diameter.
Question 8.78: Solve Prob. 8–77 if the bar has a circular cross section of ...
A=\frac{\pi}{4}\left(0.03^{2}\right)=0.225 \pi\left(10^{-3}\right) \mathrm{m}^{2}
I=\frac{\pi}{4}\left(0.015^{4}\right)=12.65625 \pi\left(10^{-9}\right) \mathrm{m}^{4}
Require \sigma_{A}=0
\sigma_{A}=0=\frac{P}{A}+\frac{M c}{I}
0=\frac{-98.1 \cos \theta}{0.225 \pi\left(10^{-3}\right)}+\frac{98.1 \sin \theta(0.015)}{12.65625 \pi\left(10^{-9}\right)}
0=-4444.44 \cos \theta+1185185.185 \sin \theta
\tan \theta=0.00375
\theta=0.215^{\circ}
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