Question 3.1: Consider the operator Q≡id/dφ where ϕ is the usual polar coo...

Consider the operator

\widehat{Q}\equiv i\frac{d}{d\phi } ,                  (3.25)

where ϕ is the usual polar coordinate in two dimensions. (This operator might arise in a physical context if we were studying the bead-on-a-ring; see Problem 2.46.) Is \widehat{Q} hermitian? Find its eigenfunctions and eigenvalues.

The Blue Check Mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

Here we are working with functions f(ϕ) on the finite interval 0≤ϕ≤2π  , with the property that

f(\phi +2\pi )=f(\phi ),      (3.26)

since ϕ and ϕ+2π describe the same physical point. Using integration by parts,

\left\langle f\mid \widehat{Q}g \right\rangle =\int_{0}^{2\pi}{f^*\left(i\frac{dg}{d\phi } \right)d\phi } = if^{*}g\mid ^{2\pi}_{0}-\int_{0}^{2\pi}{i\left(\frac{df^{*}}{d\phi } \right)}gd\phi =\left\langle \widehat{Q}f|g \right\rangle

so  \widehat{Q} is hermitian (this time the boundary term disappears by virtue of Equation 3.26). The eigenvalue equation,

i\frac{d}{d\phi }=f(\phi )=qf(\phi )       (3.27)

has the general solution

f(\phi )=Ae^{-iq\phi}     (3.28)

Equation 3.26 restricts the possible values of the q:

e^{-iq2\pi}=1\Rightarrow q=0,\pm 1,\pm 2,….       (3.29)

The spectrum of this operator is the set of all integers, and it is nondegenerate.

 

Related Answered Questions