Known A mixture of gaseous methane and oxygen, initially at 25°C and 1 atm, burns completely within a closed rigid container. The products are cooled to 900 K.
Find Determine the amount of heat transfer, in kJ, and the final pressure of the combustion products, in atm.
Schematic and Given Data:
Engineering Model
1. The contents of the closed, rigid container are taken as the system.
2. Kinetic and potential energy effects are absent, and W = 0.
3. Combustion is complete.
4. The initial mixture and the products of combustion each form ideal gas mixtures.
5. The initial and final states are equilibrium states.
Analysis The chemical reaction equation for the complete combustion of methane with oxygen is
CH4+2O2→CO2+2H2O(g)
a. With assumptions 2 and 3, the closed system energy balance takes the form
UP−UR=Q−W↗0
or
Q=UP−UR=(1uˉCO2+2uˉH2O(g))−(1uˉCH4(g)+2uˉO2)
Each coefficient in this equation is the same as the corresponding term of the balanced chemical equation.
Since each reactant and product behaves as an ideal gas, the respective specific internal energies can be evaluated as uˉ=hˉ−RˉT. The energy balance then becomes
Q=[1(hˉCO2−RˉT2)+2(hˉH2O(g)−RˉT2)]−[1(hˉCH4(g)−RˉT1)+2(hˉO2−RˉT1)]
where T1 and T2 denote, respectively, the initial and final temperatures. Collecting like terms
Q=(hˉCO2+2hˉH2O(g)−hˉCH4(g)−2hˉO2)+3Rˉ(T1−T2)
The specific enthalpies are evaluated in terms of the respective enthalpies of formation to give
1 Q=[(hˉf∘+Δhˉ)CO2+2(hˉf∘+Δhˉ)H2O(g)−(hˉf∘+Δhˉ↗0)CH4(g)−2(hˉf∘↗0+Δhˉ↗0)O2]+3Rˉ(T1−T2)
Since the methane and oxygen are initially at 25°C, Δhˉ=0 for each of these reactants. Also, hˉf∘=0 for oxygen.
With enthalpy of formation values for CO2,H2O(g) and CH4(g) from Table A-25 and enthalpy values for H2O and CO2 from Table A-23
Q=[−393,520+(37,405−9364)]+2[−241,820+(31,828−9904)]−(−74,850)+3(8.314)(298−900)
= -745,436 kJ
b. By assumption 4, the initial mixture and the products of combustion each form ideal gas mixtures. Thus, for the reactants
p1V=nRRˉT1
where nR is the total number of moles of reactants and p1 is the initial pressure. Similarly, for the products
p2V=nPRˉT2
where nP is the total number of moles of products and p2 is the final pressure.
Since nR=nP=3 and volume is constant, these equations combine to give
p2=T1T2p1=(298K900K)(1atm)=3.02atm
1 This expression corresponds to Eq. 13.17b.
Q−W=P∑n(hˉf∘+Δhˉ−RˉTP)−R∑n(hˉf∘+Δhˉ−RˉTR)=P∑n(hˉf∘+Δhˉ)−R∑n(hˉf∘+Δhˉ)−RˉTPP∑n+RˉTRR∑n (13.17b)
Skills Developed
Ability to…
• apply the closed system energy balance to a reacting system.
• evaluate property data appropriately.
• apply the ideal gas equation of state.
Quick Quiz
Calculate the volume of the system, in m3. Ans. 73.36 m3.