Question 8.60: A WT305 × 41 standard steel shape is subjected to a tension ...

A WT305 × 41 standard steel shape is subjected to a tension force P that is applied 250 mm above the bottom surface of the tee shape, as shown in Figure P8.60. If the tension normal stress of the upper surface of the WT-shape must be limited to 150 MPa, determine the allowable force P that may be applied to the member.

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Section properties (from Appendix B) 

Depth 300 mm

Centroid yˉ=88.9\bar{y}=88.9 mm (from flange to centroid)

A=5,230 mm2Iz=48.7×106 mm4\begin{aligned}&A=5,230  mm ^{2} \\&I_{z}=48.7 \times 10^{6}  mm ^{4}\end{aligned}

Stresses 

σaxial =FA=P5,230 mm2=P(1.9120×104 mm2)σbending =MzcIz=P(250 mm88.9 mm)(300 mm88.9 mm)48.7×106 mm4=P(161.1 mm)(211.1 mm)48.7×106 mm4=P(6.9832×104 mm2)\begin{aligned}&\sigma_{\text {axial }}=\frac{F}{A}=\frac{P}{5,230  mm ^{2}}=P\left(1.9120 \times 10^{-4}  mm ^{-2}\right) \\&\sigma_{\text {bending }}=\frac{M_{z} c}{I_{z}}=\frac{P(250  mm -88.9  mm )(300  mm -88.9  mm )}{48.7 \times 10^{6}  mm ^{4}} \\&=\frac{P(161.1  mm )(211.1  mm )}{48.7 \times 10^{6}  mm ^{4}} \\&=P\left(6.9832 \times 10^{-4}  mm ^{-2}\right)\end{aligned}

Normal stress on the upper surface of the WT-shape
The tension normal stress on the upper surface is equal to the sum of the axial and bending stresses. Since these stresses are expressed in terms of the unknown force P, the tension normal stress is given by:

σupper surface =P(1.9120×104 mm2)+P(6.9832×104 mm2)=(8.8953×104 mm2)P\begin{aligned}\sigma_{\text {upper surface }} &=P\left(1.9120 \times 10^{-4}  mm ^{-2}\right)+P\left(6.9832 \times 10^{-4}  mm ^{-2}\right) \\&=\left(8.8953 \times 10^{-4}  mm ^{-2}\right) P\end{aligned}

The normal stress on the upper surface of the WT-shape must be limited to 150 MPa; therefore,

(8.8953×104 mm2)P150 MPaP150 N/mm28.8953×104 mm2=168,629 N=168.6 kN\begin{aligned}\left(8.8953 \times 10^{-4}  mm ^{-2}\right) P & \leq 150  MPa \\& \therefore P \leq \frac{150  N / mm ^{2}}{8.8953 \times 10^{-4}  mm ^{-2}}=168,629  N =168.6  kN\end{aligned}

 

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