Determine the rms voltage across each resistor and the rms current in Figure 11-39.The source voltage is given as an rms value. Also determine the total power

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Accepted Answer

The total resistance of the circuit is

[latex]R_{tot}[/latex] = [latex]R_{1}[/latex] + [latex]R_{2}[/latex]= 1.0 kΩ + 560 Ω = 1.56 kΩ

Use Ohm's law to find the rms current.

[latex]I_{rms}= \frac{V_{s(rms)}}{R_{tot}}= \frac{120 \ V}{1.56 \ k\Omega } = 76.9 \ mA[/latex]

The rms voltage drop across each resistor is

[latex]V_{1(rms)}[/latex] =[latex]I_{rms} R_{1}[/latex] = (76.9 mA)(1.0 kΩ) = 76.9 V
[latex]V_{2(rms)}[/latex]= [latex]I_{rms} R_{2}[/latex] = (76.9 mA)(560 Ω ) = 43.1 V

The total power is

[latex]P_{tot}= I^{2}_{rms}R_{tot}= (76.9 \ mA)^{2}(1.56 \ k\Omega )= 9.23 \ W[/latex]

Question 11.13: Determine the rms voltage across each resistor and the rms c...

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