Question 4.40: According to Eq. 4.5, the force on a single dipole is (p · ∇...

According to Eq. 4.5, the force on a single dipole is (p · )E, so the net force on a dielectric object is

F = (p · )E                                       (4.5)

F =\int( P \cdot \nabla) E _{ ext } d \tau                                 (4.69)

[Here  E _{\text {ext }} is the field of everything except the dielectric. You might assume that it wouldn’t matter if you used the total field; after all, the dielectric can’t exert a force on itself. However, because the field of the dielectric is discontinuous at the location of any bound surface charge, the derivative introduces a spurious delta function, and it is safest to stick with E _{\text {ext }} Use Eq. 4.69 to determine the force on a tiny sphere, of radius R, composed of linear dielectric material of susceptibility \chi_{e} , which is situated a distance s from a fine wire carrying a uniform line charge λ.

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E _{ ext }=\frac{\lambda}{2 \pi \epsilon_{0} s} \hat{ s } . Since the sphere is tiny, this is essentially constant, and hence P =\frac{\epsilon_{0} \chi_{e}}{1+\chi_{e} / 3} E _{\text {ext }} (Ex. 4.7).

F =\int\left(\frac{\epsilon_{0} \chi_{e}}{1+\chi_{e} / 3}\right)\left(\frac{\lambda}{2 \pi \epsilon_{0} s}\right) \frac{d}{d s}\left(\frac{\lambda}{2 \pi \epsilon_{0} s}\right) \hat{ s } d \tau=\left(\frac{\epsilon_{0} \chi_{e}}{1+\chi_{e} / 3}\right)\left(\frac{\lambda}{2 \pi \epsilon_{0}}\right)^{2}\left(\frac{1}{s}\right)\left(\frac{-1}{s^{2}}\right) \hat{ s } \int d \tau

 

=\frac{-\chi_{e}}{1+\chi_{e} / 3}\left(\frac{\lambda^{2}}{4 \pi^{2} \epsilon_{0}}\right) \frac{1}{s^{3}} \frac{4}{3} \pi R^{3} \hat{ s }=-\left(\frac{\chi_{e}}{3+\chi_{e}}\right) \frac{\lambda^{2} R^{3}}{\pi \epsilon_{0} s^{3}} \hat{ s }

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