Refer to Figure 19-15. Determine V_{th} for the circuit within the beige box as viewed from terminals A and B.
Refer to Figure 19-15. Determine V_{th} for the circuit within the beige box as viewed from terminals A and B.
Remove R_{L} and determine the voltage from A to B ( V_{th}). In this case, the voltage from A to B is the same as the voltage across X_{L}. This is determined using the voltage-divider method.
V_{L}= \left(\frac{X_{L}\angle 90°}{R_{1}+ jX_{L}} \right)V_{s}= \left(\frac{50\angle 90°\Omega }{100 \ \Omega + j50 \ \Omega } \right)V_{s}\ \ \ \ \ =\left(\frac{50\angle 90°\Omega }{112\angle 26.6°\Omega} \right)25\angle 0°V= 11.2\angle 63.4°V
V_{th}= V_{AB}= V_{L}= 11.2\angle 63.4°V