Refer to Figure 19-22. Determine Z_{th} for the portion of the circuit within the beige box as viewed from terminals A and B. This is the same circuit as in Example 19-6.
Refer to Figure 19-22. Determine Z_{th} for the portion of the circuit within the beige box as viewed from terminals A and B. This is the same circuit as in Example 19-6.
With the voltage source replaced by its internal impedence (zero in this case), X_{L} is effectively out of the circuit. R and C appear in parallel when viewed from the open terminals, as indicated in Figure 19-23. Z_{th} is calculated as follows:
Z_{th}= \frac{(R \angle 0°)(X_{C}\angle -90°)}{R -jX_{C}} = \frac{(10 \angle 0°k\Omega )(10\angle -90°k\Omega )}{10 \ \Omega -j10 \ k\Omega }\ \ \ \ \ \ =\frac{(10 \angle 0°k\Omega )(10\angle -90°k\Omega )}{14.1\angle -45°k\Omega }= 7.07\angle -45°k\Omega