Question 19.9: Refer to Figure 19-22. Determine Zth for the portion of the ...

Refer to Figure 19-22. Determine Z_{th} for the portion of the circuit within the beige box as viewed from terminals A and B. This is the same circuit as in Example 19-6.

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With the voltage source replaced by its internal impedence (zero in this case), X_{L} is effectively out of the circuit. R and C appear in parallel when viewed from the open terminals, as indicated in Figure 19-23. Z_{th} is calculated as follows:

Z_{th}= \frac{(R \angle 0°)(X_{C}\angle -90°)}{R -jX_{C}} = \frac{(10 \angle 0°k\Omega )(10\angle -90°k\Omega )}{10 \ \Omega -j10 \ k\Omega }

 

\ \ \ \ \ \ =\frac{(10 \angle 0°k\Omega )(10\angle -90°k\Omega )}{14.1\angle -45°k\Omega }= 7.07\angle -45°k\Omega
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