Question 20.9: Draw the output voltage for the RL differentiator in Figure ...

First, calculate the time constant,

In this case, t_{W}= 5 \tau , so the output will decay to zero at the end of the pulse. On the rising edge, the inductor voltage jumps to +5 V and then decays exponentially to zero. It reaches approximately zero at the instant of the falling edge. On the falling edge of the input, the inductor voltage jumps to —5 V and then goes back to zero. The output waveform is shown in Figure 20-44.