Question 4.12: Stoichiometry . When urea, (NH)2 2CO, is acted on by the enz...

For grams of CO_{2}:

Step 1: We first convert moles of urea to moles of carbon dioxide, using the conversion factor derived from the balanced chemical equation, 1 mol urea = 1 mol carbon dioxide.

0.83 \cancel{mol  urea} \times \frac{1 mol CO_{2} }{1 \cancel{mol  urea} } = mol CO_{2}

Step 2: Use the conversion factor 1 mol CO_{2} = 44 g CO_{2} and then do the math to give the answer:

0.83 \cancel{mol  urea} \times \frac{1 \cancel{mol  CO_{2}} }{1 \cancel{mol  urea} }\times \frac{44 g CO_{2} }{1\cancel{mol  CO_{2}} } =37 g CO_{2}

For grams of NH_{3} :

Steps 1 and 2 combined into one equation: We follow the same procedure as for CO_{2}but use different conversion factors:

0.83 \cancel{mol  urea} \times \frac{2 \cancel{mol  NH_{3}} }{1 \cancel{mol  urea} }\times \frac{17  g  NH_{3} }{1\cancel{mol  NH_{3}} } =28 g NH_{3}