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Question 12.22: A three-cylinder radial engine (Fig.12.43) driven by a commo...

A three-cylinder radial engine (Fig.12.43) driven by a common crank has the cylinders spaced at 120°. The stroke is 120 mm, length of connecting rod 240 mm and the mass of the reciprocating parts per cylinder is 1 kg and the speed of the crank shaft is 2400 rpm. Determine the magnitude of the primary and secondary forces.

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\text { Given: } r=60 mm , l=240 mm , M=1 kg , N=2400 rpm .

Maximum primary force

=1.5 Mr \omega^{2} .

=1.5 \times 1 \times 0.06 \times\left(2 \pi \times \frac{2400}{60}\right)^{2} .

=5684.9 N .

B 1 \beta 1=1.5 M\rho .

=1.5 \times 1 \times 0.06 .

=0.09 N \cdot m .

\text { Maximum secondary force }=1.5 M \times(2 \omega)^{2} \times \frac{r}{4 n} .

=1.5 \times 1 \times 0.06 \times \frac{\left(4 \pi \times \frac{2400}{60}\right)^{2}}{16}=1421.2 N .

B_{2} b_{2}=\frac{1.5 Mr }{4 n}=\frac{1.5 \times 1 \times 0.06}{4 \times 4}=0.005625 Nm .

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