Two crossed shafts are connected by helical gears. The velocity ratio is 18:1 and the shaft angle is 45°. If d_{1}=60 mm \text { and } d_{2}=95 mm , calculate the helix angles if both gears have the same hand.
Two crossed shafts are connected by helical gears. The velocity ratio is 18:1 and the shaft angle is 45°. If d_{1}=60 mm \text { and } d_{2}=95 mm , calculate the helix angles if both gears have the same hand.
Given: i=1.8, d_{1}=60 mm , d_{2}=95 mm , \Sigma=45^{\circ} .
i=d_{2} \cos \beta_{2} /\left(d_{1} \cos \beta_{1}\right) .
1.8=(95 / 60)\left(\cos \beta_{2} / \cos \beta_{1}\right) .
\left(\cos \beta_{2} / \cos \beta_{1}\right)=1.1368 .
\Sigma=\beta_{1}+\beta_{2}=45^{\circ} .
\cos \left(45^{\circ}-\beta_{1}\right)=1.1368 \cos \beta_{1} .
\tan \beta_{1}=0.60798 .
\beta_{1}=31.3^{\circ}, \beta_{2}=13.7^{\circ} .