Question 14.33: Two crossed shafts are connected by helical gears. The veloc...

Two crossed shafts are connected by helical gears. The velocity ratio is 18:1 and the shaft angle is 45°. If d_{1}=60 mm \text { and } d_{2}=95 mm , calculate the helix angles if both gears have the same hand.

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Given:    i=1.8, d_{1}=60 mm , d_{2}=95 mm , \Sigma=45^{\circ} .

i=d_{2} \cos \beta_{2} /\left(d_{1} \cos \beta_{1}\right) .

1.8=(95 / 60)\left(\cos \beta_{2} / \cos \beta_{1}\right) .

\left(\cos \beta_{2} / \cos \beta_{1}\right)=1.1368 .

\Sigma=\beta_{1}+\beta_{2}=45^{\circ} .

\cos \left(45^{\circ}-\beta_{1}\right)=1.1368 \cos \beta_{1} .

\tan \beta_{1}=0.60798 .

\beta_{1}=31.3^{\circ}, \beta_{2}=13.7^{\circ} .

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