Synthesize a slider-crank mechanism for its three positions \theta_{12}=60^{\circ} \text { and } \theta_{13}=100^{\circ} of the input crank and three positions x_{12}=2 cm \text { and } x_{13}=5 cm of the output slider block. The eccentricity is 2 cm. The slider is moving outwards.
Question 16.10: Synthesize a slider-crank mechanism for its three positions ...
Refer to Fig.16.24.
\text { 1. Draw two parallel lines } l_{1} \text { and } l_{2} \text { at eccentricity, } e=2 cm .
\text { 2. Select an arbitrary point } O_{2} \text { on } l_{1} \text {. Measure } O_{2} C_{1}=x_{12} / 2=1 cm \text { and } O_{2} C_{2}=x_{13 / 2}=2.5 cm \text { to the left } \text { of } O_{2} . \text { Draw } O_{2} P_{1}, C_{1} P_{2}, C_{2} P_{3} \text { perpendiculars on line } l_{1}.
\text { 3. Draw } \angle P_{1} O_{2} P_{4}=\theta_{12} / 2=30^{\circ} \text { and } \angle P_{1} O_{2} P_{5}=\theta_{13} / 2=50^{\circ} \text { in the anti-clockwise direction } .
\text { 4. Produce } O_{2} P_{4} \text { and } O_{2} P_{5} \text { lines to meet the perpendiculars at } C_{1} \text { and } C_{2} \text { to locate the relative poles } R_{12} \text { and } R_{13}.
\text { 5. Join } R_{12} B \text { and } R_{13} B .
\text { 6. Draw } \angle B R_{12} M_{1}=\theta_{12} / 2=30^{\circ} \text { and } \angle B R_{13} M_{2}=\theta_{13} / 2=50^{\circ} \text { in the anti-clockwise direction. Produce }\text { the lines } R_{12} M_{1} \text { and } R_{13} M_{2} \text { backward to meet at } A .
\text { 7. Join } A B \text { and } A O_{2} \text { to get the coupler and input crank respectively } .
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