For the 4 bit DAC shown in the figure, the output voltage V0 is
(a) 10 V (b) 5 V
(c) 4 V (d) 8 V
For the 4 bit DAC shown in the figure, the output voltage V0 is
(a) 10 V (b) 5 V
(c) 4 V (d) 8 V
At non-inv terminal:
\begin{aligned}&\left(1+\frac{7\not{k}}{1 \not{k}}\right)=8 \Rightarrow V_{0}=\left(0+\frac{1}{8}+\frac{1}{2}+0\right) \times 8=\frac{5}{\not{8}} \times \not{8} \\&V^{0}=5 V\end{aligned}Hence, the correct option is (b).