Question 11.34: A gear-reduction unit uses the countershaft depicted in the ...

A gear-reduction unit uses the countershaft depicted in the figure. Find the two bearing reactions. The bearings are to be angular-contact ball bearings, having a desired life of 50 kh when used at 300 rev/min. Use 1.2 for the application factor and a reliability goal for the bearing pair of 0.96. Select the bearings from Table 11–2.

A gear-reduction unit uses the countershaft depicted in the figure. Find the two bearing reactions. The bearings are to be angular-contact ball bearings, having a desired life of 50 kh when used at 300 rev/min. Use 1.2 for the application factor and a reliability goal for the bearing pair of 0.96.

 

Table 11–2
Dimensions and Load Ratings for Single-Row 02-Series Deep-Groove and Angular-Contact Ball Bearings
Bore, mm OD,
mm
Width, m m Fillet Radius, mm shoulder
Diameter, mm
Load Ratings, kN
Deep Groove Angular Contact
d _{ s } d _{ H } C_{10} C_{0} C_{10} C_{0}
10 30 9 0.6 12.5 27 5.07 2.24 4.94 2.12
12 32 10 0.6 14.5 28 6.89 3.10 7.02 3.05
15 35 11 0.6 17.5 31 7.80 3.55 8.06 3.65
17 40 12 0.6 19.5 34 9.56 4.50 9.95 4.75
20 47 14 1.0 25 41 12.7 6.20 13.3 6.55
25 52 15 1.0 30 47 14.0 6.95 14.8 7.65
30 62 16 1.0 35 55 19.5 10.0 20.3 11.0
35 72 17 1.0 41 65 25.5 13.7 27.0 15.0
40 80 18 1.0 46 72 30.7 16.6 31.9 18.6
45 85 19 1.0 52 77 33.2 18.6 35.8 21.2
50 90 20 1.0 56 82 35.1 19.6 37.7 22.8
55 100 21 1.5 63 90 43.6 25.0 46.2 28.5
60 110 22 1.5 70 99 47.5 28.0 55.9 35.5
65 120 23 1.5 74 109 55.9 34.0 63.7 41.5
70 125 24 1.5 79 114 61.8 37.5 68.9 45.5
75 130 25 1.5 86 119 66.3 40.5 71.5 49.0
80 140 26 2.0 93 127 70.2 45.0 80.6 55.0
85 150 28 2.0 99 136 83.2 53.0 90.4 63.0
90 160 30 2.0 104 146 95.6 62.0 106 73.5
95 170 32 2.0 110 156 108 69.5 121 85.0
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R=\sqrt{0.96}=0.980

 

T=12\left(240 \cos 20^{\circ}\right)=2706  lbf \cdot in

 

F=\frac{2706}{6 \cos 25^{\circ}}=498  lbf

 

In xy-plane:

\Sigma M_{O}^{z}=-16(82.1)-30(210)+42 R_{C}^{y}=0

 

\begin{aligned}&R_{C}^{y}=181  lbf \\&R_{O}^{y}=82.1+210-181=111.1  lbf\end{aligned}

In xz-plane:

\begin{aligned}&\Sigma M_{O}^{y}=16(226)-30(451)-42 R_{C}^{z}=0 \\&R_{C}^{z}=-236  lbf \\&R_{O}^{z}=226-451+236=11  lbf \\&R_{O}=\left(111.1^{2}+11^{2}\right)^{1 / 2}=112  lbf  \\&R_{C}=\left(181^{2}+236^{2}\right)^{1 / 2}=297  lbf  \\&x_{D}=\frac{50000(300)(60)}{10^{6}}=900\end{aligned}

 

\begin{aligned}\left(C_{10}\right)_{o} &=1.2(112)\left\{\frac{900}{0.02+4.439[\ln (1 / 0.980)]^{1 / 1.483}}\right\}^{1 / 3} \\&=1860  lbf =8.28  kN\end{aligned}

 

\begin{aligned}\left(C_{10}\right)_{C} &=1.2(297)\left\{\frac{900}{0.02+4.439[\ln (1 / 0.980)]^{1 / 1.483}}\right\}^{1 / 3} \\&=4932  lbf =21.9  kN\end{aligned}

 

Bearing at O: Choose a deep-groove 02-17 mm.
Bearing at C: Choose a deep-groove 02-35 mm.

 

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