How many grams of potassium hydroxide are required to prepare 600. mL of 0.450 M KOH solution?
How many grams of potassium hydroxide are required to prepare 600. mL of 0.450 M KOH solution?
Solution map: milliliters→liters→moles→grams
PLAN Knowns volume = 600. mL M= \frac{0.450 mol}{L}
molar mass KOH= \frac{56.11 g}{mol}
CALCULATE (600. \cancel{mL}) (\frac{1 \cancel{L}}{1000 \cancel{mL}} ) (\frac{0.450 \cancel{mol}}{\cancel{L}} ) (\frac{56.11 g KOH}{\cancel{mol}} ) = 15.1 g KOH