Question 14.11: How many milliliters of 2.00 M HCl will react with 28.0 g Na...

READ     Knowns      mass = 28.0 g NaOH

M = 2.00 mol/L HCl

PLAN      Write a balanced equation for the reaction

HCl(aq) + NaOH(aq)→ NaCl(aq) + H_2O(l)

Find the number of moles NaOH in 28.0 g NaOH.

Solution map:        grams NaOH → moles NaOH

(28.0 \cancel{g   NaOH}) (\frac{1   mole}{40.00   \cancel{g   NaOH}} ) = 0.700 mol NaOH

SETUP      Solution map:    mol NaOH → mol HCl→ L HCl → mL HCl

CALCULATE  (0.700    \cancel{mol   NaOH}) (\frac{1  \cancel{mol   HCl}}{1  \cancel{mol   NaOH}} ) (\frac{1   L   HCl }{2.00  \cancel{mol   HCl}} ) = 0.350 L HCl

= 350. mL HCl