Question 3.6.4: Let E1 = [1 0 0 2 1 0 0 0 1], E2 = [1 0 0 0 1 0 0 0 3], and ...

Let E_{1} = \left [ \begin{matrix} 1 & 0 & 0 \\ 2 & 1 & 0 \\ 0 & 0 & 1 \end{matrix} \right ] , E_{2} = \left [ \begin{matrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 3 \end{matrix} \right ] , and A = \left [ \begin{matrix} 1 & 1 & 3 \\ 0 & -1 & 2 \\ 0 & 5 & 6 \end{matrix} \right ] . Calculate E_{1}A and E_{2}E_{1}A . Describe the products in terms of matrices obtained from A by elementary row operations.

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By matrix multiplication, we get

E_{1}A = \left [ \begin{matrix} 1 & 0 & 0 \\ 2 & 1 & 0 \\ 0 & 0 & 1 \end{matrix} \right ] \left [ \begin{matrix} 1 & 1 & 3 \\ 0 & -1 & 2 \\ 0 & 5 & 6 \end{matrix} \right ] = \left [ \begin{matrix} 1 & 1 & 3 \\ 2 & 1 & 8 \\ 0 & 5 & 6 \end{matrix} \right ]

Observe that E_{1}A is the matrix obtained from A by performing the row operation R_{2} + 2R_{1} . That is, by performing the row operation associated with E_{1}.

E_{2}E_{1}A = \left [ \begin{matrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 3 \end{matrix} \right ] \left [ \begin{matrix} 1 & 1 & 3 \\ 2 & 1 & 8 \\ 0 & 5 & 6 \end{matrix} \right ] = \left [ \begin{matrix} 1 & 1 & 3 \\ 2 & 1 & 8 \\ 0 & 15 & 18 \end{matrix} \right]

Thus, E_{2}E_{1}A is the matrix obtained from A by first performing the row operation R_{2} + 2R_{1}, and then performing the row operation associated with E_{2}, namely 3R_{3}.

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