A silicon diode has a saturation current of 7.5 μA at room temperature 300 K. Calculate the saturation current at 400 K.
Question 4.23: A silicon diode has a saturation current of 7.5 μA at room t...
Given I_{o1} = 7.5 × 10 ^{– 6} A at T_{1} = 300 K = 27°C and T_{2} = 400 K = 127°C
Therefore, the saturation current at 400 K is
I_{o2} = I_{o1} × 2 ^{(T_{2} – T_{1})/10}
= 7.5 × 10^{ – 6} × 2^{ (127 – 27)/10}
= 7.5 × 10 ^{– 6} × 2^{10} = 7.68 mA
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