Draw mirror-image isomers for any of the following compounds that can exist as enantiomers:

(a) $CH_3CH_2CH_2OH$ (c) $CH_3CH_2CHClCH_2CH_2CH_3$

(b) $CH_3CH_2CHClCH_2CH_3$

Question

Draw mirror-image isomers for any of the following compounds that can exist as enantiomers:

(a) [latex]CH_3CH_2CH_2OH[/latex] (c) [latex]CH_3CH_2CHClCH_2CH_2CH_3[/latex]

(b) [latex]CH_3CH_2CHClCH_2CH_3[/latex]

Accepted Answer

First check each formula for chiral carbon atoms:
(a) No chiral carbon atoms; each carbon has at least two groups that are the same.
(b) No chiral carbon atoms; carbon 3 has H, Cl, and two [latex]CH_3CH_2[/latex] groups.
(c) Carbon 3 is chiral; the four groups on carbon 3 are H, Cl, [latex]CH_3CH_2[/latex], and [latex]CH_3CH_2CH_2[/latex]. Draw mirror images:

Question 26.2: Draw mirror-image isomers for any of the following compounds...

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