Using the International Building Code from Table 9.11 (maximum floor area allowances per occupant) for industrial areas, 100 ft^2 per occupant is the recommended area: Maximum population = 120 ft × 200 ft / 100 ft^2/person = 240 people From Table 9.12 (minimum number of exits for occupant load), gi

Question

Using the International Building Code from Table [latex]9.11[/latex] (maximum floor area allowances per occupant) for industrial areas, [latex]100 \mathrm{ft}^{2}[/latex] per occupant is the recommended area:

[latex]\begin{aligned} ext { Maximum population } &=\frac{120 \mathrm{ft} imes 200 \mathrm{ft}}{100 \mathrm{ft}^{2} / ext { person }} \&=240 ext { people }\end{aligned}[/latex]

From Table [latex]9.12[/latex] (minimum number of exits for occupant load), given the population, the minimum number of exits required is two.

From Table 9.13, the remoteness requirements can be addressed. That is, how far apart should these doors be to safely move occupants out of the facility?

Table 9.11 (2003 IBC Table 1004.1.2) Maximum Floor Area Allowances per Occupant
Use	Floor Area per Occupant ([latex]ft^{2} [/latex])
Agricultural building	300 gross
Aircraft hangers	500 gross
Airport terminal
Baggage claim	20 gross
Baggage handling	300 gross
Concourse	100 gross
Waiting areas	15 gross
Assembly
Gaming floors (keno, slots, etc.)	11 gross
Assembly with fixed seats	See Section 1003.2.2.9
Assembly without fixed seats
Concentrated (chairs only—not fixed)	7 net
Standing space	3 net
Unconcentrated (tables and chairs)	15 net
Bowling alleys allow five persons for each alley, including
15′ of runway, and for additional areas	7 net
Business areas	100 gross
Court rooms—other than fixed seating areas	40 net
Dormitories	50 gross
Educational
Classroom area	20 net
Shops and other vocational room areas	50 net
Exercise rooms	50 gross
H-5 fabrication and manufacturing areas	200 gross
Industrial areas	100 gross
Institutional areas
Inpatient treatment areas	240 gross
Outpatient areas	100 gross
Sleeping areas	120 gross
Kitchen, commercial	200 gross
Library
Reading rooms	50 net
Stack areas	100 gross
Mercantile
Basement and grade floor areas	30 gross
Areas on other floors	60 gross
Storage, stock, shipping areas	300 gross
Parking garages	200 gross
Residential	200 gross
Skating rinks, swimming pools
Rink and pool	50 gross
Decks	15 gross
Stages and platforms	15 net
Accessory storage areas, mechanical
equipment room	300 gross
Warehouses	500 gross
Note: 1 ft = 304.8 mm; 1 [latex]ft^{2} [/latex]= 0.093 m.
Source: 2003 IBC [3].

Table 9.12 (BOAC Table 809.2) Minimum Number of Exits for Occupant Load
Occupant Load	Minimum Number of Exits
500 or less	2
501–1000	3
Over 1000	4
Source: 2003 IBC [3].

Table 9.13 2003 IBC Remoteness Requirements

1014.2.1 Two exits or exit access doorways. Where two exits or exit access doorways
are required from any portion of the exit access, the exit doors or exit access doorways
shall be placed a distance apart equal to not less than one-half of the length of the
maximum overall diagonal dimension of the building or area to be served measured in a
straight line between exit doors or exit access doorways. Interlocking or scissor stairs shall
be counted as one exit stairway.

Source: 2003 IBC [3].

Accepted Answer

For the building shown in Figure [latex]9.12[/latex],

[latex]\begin{aligned} ext { The distance between exits }&=\frac{ ext { The diagonal dimension }}{4}=\frac{d}{4} \d &=\left(\left(200^{\prime} ight)^{2}+\left(120^{\prime} ight)^{2} ight)^{1 / 2}=233^{\prime}\end{aligned}[/latex]

Minimum distance between exits [latex]=\frac{233^{\prime}}{4}=58^{\prime}[/latex]

Note: If the building does not have sprinklers, exits should be [latex]d / 2[/latex].

Using Table [latex]9.12[/latex], we can now determine the allowable minimum width for each door

Capacity per exit [latex]=\frac{240 ext { people }}{2 ext { exits }}=120[/latex] people/exit

Minimum width [latex]=120 imes 0.2^{\prime \prime}=24^{\prime \prime}[/latex]

Since the minimum width is below the [latex]2^{\prime} 8^{\prime \prime}[/latex] recommended for barrier-free access, each door should be increased to [latex]2^{\prime} 8^{\prime \prime}[/latex] in width (see Figure [latex]9.13[/latex] ). Finally, check the recommended solution to determine if the allowable length of travel exiting the building is satisfied. From Table [latex]9.14[/latex], for use group (I) with fire suppression, travel distance to exits is okay.

The planner must balance the number of exits with the maximum allowable travel distance required by code. From Table 9.14, the maximum allowable travel distance for industrial use groups with a fire suppression system is 250 feet. This suggests that both doors could be on the same elevation of the warehouse.

Table 9.14 Length of Exit Access Travel ( feet)
Use Group	Without Fire Suppression System	With Fire Suppression System
A, B, E, F-1, I-1, M, R, S-1	200	250
F-2, S-2, U	300	400
H	---	200
I-2, I-3, I-4	150	200
Source: 2003 IBC [3].

Question 9.6: Using the International Building Code from Table 9.11 (maxim...

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