Question 22.3: For the iron-core transformer in Fig. 22.6: a. Find the magn...
For the iron-core transformer in Fig. 22.6:
a. Find the magnitude of the current in the primary and the impressed voltage across the primary.
b. Find the input resistance of the transformer.
\text { a. } \frac{I_{p}}{I_{s}}=\frac{N_{s}}{N_{p}}.
I_{p}=\frac{N_{s}}{N_{v}} I_{s}=\left(\frac{5 t }{40 t }\right)(0.1 A )=12.5 mA.
V_{L}=I_{s} Z_{L}=(0.1 A )(2 k \Omega)=200 V.
Also, \frac{V_{g}}{V_{L}}=\frac{N_{p}}{N_{s}}.
V_{g}=\frac{N_{p}}{N_{s}} V_{L}=\left(\frac{40 t }{5 t }\right)(200 V )=1600 V.
\text { b. } Z_{p}=a^{2} Z_{L}.
a=\frac{N_{p}}{N_{s}}=8.
Z_{p}=(8)^{2}(2 k \Omega)=R_{p}=128 k \Omega.
Related Answered Questions
Question: 22.4
Verified Answer:
\text { a. } \quad P_{T}=(10)(60 W )+200 W ...
Question: 22.9
Verified Answer:
For each coil, the mutual term is positive, and th...
Question: 22.8
Verified Answer:
\text { Coil 1: } \quad L_{1}\overset{\ove...
Question: 22.10
Verified Answer:
Z _{i}= Z _{p}+\frac{(\omega M)^{2}}{ Z _{s...
Question: 22.7
Verified Answer:
\text { a. } R_{e}=R_{p}+a^{2} R_{s}=1 \Ome...
Question: 22.6
Verified Answer:
a. Ideally, the primary power equals the power del...
Question: 22.5
Verified Answer:
a. The source current:
I_{s}=\frac{E}{R_{T}...
Question: 22.2
Verified Answer:
\text { a. } E_{p}=4.44 N_{p} f \Phi_{m}[/l...
Question: 22.1
Verified Answer:
\text { a. } M=k \sqrt{L_{p} L_{s}}=0.6 \sq...