Question 22.2: For the iron-core transformer in Fig. 22.5: a. Find the maxi...
For the iron-core transformer in Fig. 22.5:
a. Find the maximum flux \Phi_{m}.
b. Find the secondary turns N_{s} .
\text { a. } E_{p}=4.44 N_{p} f \Phi_{m}.
\text { Therefore, } \Phi_{m}=\frac{E_{p}}{4.44 N_{p} f}=\frac{200 V }{(4.44)(50 t )(60 Hz )}.
and
\Phi_{m}=15.02 mWb.
\text { b. } \frac{E_{p}}{E_{s}}=\frac{N_{p}}{N_{s}}.
Therefore,
N_{s}=\frac{N_{p} E_{s}}{E_{p}}=\frac{(50 t )(2400 V )}{200 V }.
= 600 turns.
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