Question 24.6: Determine the average value for the periodic pulse waveform ...
Determine the average value for the periodic pulse waveform in Fig. 24.15.
By the method in Section 13.7,
G=\frac{\text { area under curve }}{T}.
T=(12-2) \mu s =10 \mu s.
G=\frac{(8 mV )(4 \mu s )+(2 mV )(6 \mu s )}{10 \mu s }=\frac{32 \times 10^{-9}+22 \times 10^{-9}}{10 \times 10^{-6}}.
=\frac{44 \times 10^{-9}}{10 \times 10^{-6}}=4.4 mV.
By Eq. (24.5),
V_{ av }=(\text { duty cycle })(\text { peak value })+(1-\text { duty cycle })\left(V_{b}\right) (24.5).
V_{b}=+2 mV.
\text { Duty cycle }=\frac{t_{p}}{T}=\frac{(6-2) \mu s }{10 \mu s }=\frac{4}{10}=0.4 \text { (decimal form) }.
\text { Peak value (from } 0 V \text { reference })=8 mV.
V_{\text {av }}=(\text { duty cycle })(\text { peak value })+(1-\text { duty cycle })\left(V_{b}\right).
=(0.4)(8 mV )+(1-0.4)(2 mV ).
=3.2 mV +1.2 mV = 4 . 4 m V.
as obtained above.