Question 12.11: For the circuit of Fig. 12.19 , calculate the maximum input ...
For the circuit of Fig. 12.19 , calculate the maximum input power, maximum output power, input voltage for maximum power operation, and power dissipated by the output transistors at this voltage.
The maximum input power is
\operatorname{maximum} P_{i}( dc )=\frac{2 V_{C C}^{2}}{\pi R_{L}}=\frac{2(25 V )^{2}}{\pi 4 \Omega}= 9 9 . 4 7 WThe maximum output power is
\operatorname{maximum} P_{o}( ac )=\frac{V_{C C}^{2}}{2 R_{L}}=\frac{(25 V )^{2}}{2(4 \Omega)}=78.125 W[Note that the maximum efficiency is achieved:
\left.\% \eta=\frac{P_{o}}{P_{i}} \times 100 \%=\frac{78.125 W }{99.47 W } 100 \%=78.54 \%\right]To achieve maximum power operation the output voltage must be
V_{L}( p )=V_{C C}=25 Vand the power dissipated by the output transistors is then
P_{2 Q}=P_{i}-P_{o}=99.47 W -78.125 W =21.3 W
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