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Question 7.2: (a) Find the expression for the current I for the transistor...

(a) Find the expression for the current I for the transistor connection shown if γ = 1.
(b) How does the current I divide between the base lead and the collector lead?

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(a) SinceV_{CB} =0 Eq. (7–8b) gives \Delta p_{C} =0

\Delta p_{C} =p_{n}\left(e^{q^{{V_{CB} }/{KT}} } -1\right)   (7–8b)

Thus from Eq. (7–18a),

I_{Ep} =qA\frac{D_{p} }{L_{p}} \left(\Delta p_{E} ctnh\frac{W_{p}}{L_{p}} -\Delta p_{c}csch\frac{W_{p}}{L_{p}}\right)  (7–18a)

 

I_{E}=I=\frac{qAD_{p} }{L_{p}}\Delta p_{E} ctnh\frac{W_{p}}{L_{p}}

 

(b) I_{C}=\frac{qAD_{p} }{L_{p}}\Delta p_{E} csch\frac{W_{p}}{L_{p}}

 

I_{B}=\frac{qAD_{p} }{L_{p}}\Delta p_{E} tanh\frac{W_{p}}{2L_{p}}

 

where I_{C}and I_{B}are the components in the collector lead and base lead,
respectively. Note that these results are analogous to those of Probs. 5.40
and 5.41 for the narrow base diode.

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