Question 18.32: In a Zener regulator, the d.c. input is 10V ± 20%. The outpu...

In a Zener regulator, the d.c. input is 10V ± 20%. The output requirements are 5 V, 20 mA. Assume I_{z(min)} and I_{z(max)} as 5 mA and 80A. Design the Zener regulator.

The Blue Check Mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

The minimum Zener current is I_{z (min)} = 5 mA when the input voltage is minimum. Here the input voltage varies between 10 V ± 20% i.e. 8 V and 12 V.
Therefore, the input voltage V_{i(min)} = 8 V
Given load current I_{L} = 20 mA and the voltage across the load, V_{0} = 5 V.
Therefore,

R_{L} =\frac{V0}{I_L}=\frac{5\,V}{20 × 10^{– 3}}= 250 Ω

Hence, the series resistance

R =\frac{V_{i(min)} – V_{0}}{(I_{z(min)} + I_{L})}

= \frac{(8 – 5)}{(5 + 20) × 10^{– 3}} = 120 Ω

The various values are given in the Zener regulator shown in Fig. 18.20.

32

Related Answered Questions