Question 12.5: In a hydraulics laboratory, a flow of 0.412 m^3/s was measur...

In a hydraulics laboratory, a flow of 0.412 \mathrm{~m}^{3} / \mathrm{s} was measured from a rectangular channel flowing 1.22 m wide and 0.61 m deep. If the slope of the channel was 0.0004, find its roughness factor using Manning’s formula.

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Here,

A=1.22 \times(0.61) =0.7442 \mathrm{~m}^{2}  P=1.22+2 \times 0.61=2.44 

Therefore, R_{h}=A / P=0.305 \mathrm{~m} 

Using Eq. (12.9)
V=(1 / n) R_{h}^{2 / 3} S^{1 / 2}               (12.9)

Q=0.412=\frac{1.22 \times 0.610}{n}(0.305)^{2 / 3}(0.0004)^{1 / 2} 

Which gives        n = 0.0163

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