Question 8.7: Calculating pOH The [OH^-] of a strongly basic solution is 1...

Calculating pOH

The \left[ OH ^{-}\right] of a strongly basic solution is 1.0 \times 10^{-2}. What are the pOH and pH of this solution?

Strategy

When given the \left[ OH ^{-}\right], determine the pOH by taking the negative logarithm. To calculate the pH, subtract the pOH from 14.

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The pOH is -log 1.0 \times 10^{-2} or 2, and the pH is 14 – 2 = 12.

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