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Question 3.1: Find the period of the machine cycle for 11.0592 MHz crystal...

Find the period of the machine cycle for 11.0592 MHz crystal frequency

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11.0592/12 = 921.6 kHz;

machine cycle is 1/921.6 kHz = 1.085μs

Related Answered Questions

Question: 3.7

For an AT8051 and DSC89C4x0 system of 11.0592 MHz, find how long it takes to execute each instruction. (a) MOV R3,#55 (b) DEC R3 (c) DJNZ R2 target (d) LJMP (e) SJMP (f) NOP (g) MUL AB ...

Verified Answer:

AT8051                                        DS89...
Question: 3.6

Find the period of the machine cycle (MC) for various versions of 8051, if XTAL=11.0592 MHz. (a) AT89C51 (b) P89C54X2 (c) DS5000 (d) DS89C4x0 ...

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(a)       11.0592MHz/12 = 921.6kHz; MC is 1/921.6k...
Question: 3.5

Find the size of the delay in following program, if the crystal frequency is 11.0592MHz. Machine Cycle DELAY: MOV R2,#200 1 AGAIN: MOV R3,#250 1 HERE: NOP 1 NOP 1 DJNZ R3,HERE 2 DJNZ R2,AGAIN 2 RET 2 ...

Verified Answer:

For HERE loop, we have (4x250) x1.085 μs＝1085μs. ...
Question: 3.4

Find the size of the delay in following program, if the crystal frequency is 11.0592MHz. Machine Cycle DELAY: MOV R3,#250 1 HERE: NOP 1 NOP 1 NOP 1 NOP 1 DJNZ R3,HERE 2 RET 2 ...

Verified Answer:

The time delay inside HERE loop is [250 ( 1 + 1 + ...
Question: 3.3

Find the size of the delay in following program, if the crystal frequency is 11.0592MHz. MOV A,#55H AGAIN: MOV P1,A ACALL DELAY CPL A SJMP AGAIN ;—time delay——- DELAY: MOV R3,#200 HERE: DJNZ R3,HERE RET ...

Verified Answer:

Machine cycle DELAY:        MOV      R3,#200      ...
Question: 3.2

For 8051 system of 11.0592 MHz, find how long it takes to execute each instruction. (a) MOV R3,#55 (b) DEC R3 (c) DJNZ R2 target (d) LJMP (e) SJMP (f) NOP (g) MUL AB ...

Verified Answer:

Machine cycles Time to execute (a) 1 1x1.085μs ...