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Question 3.4: Find the size of the delay in following program, if the crys...

Find the size of the delay in following program, if the crystal frequency is 11.0592MHz.

Machine Cycle

DELAY:        MOV    R3,#250                  1
HERE:          NOP                                     1

NOP                                     1
NOP                                     1
NOP                                     1
DJNZ    R3,HERE               2
RET                                      2
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The time delay inside HERE loop is

[250 ( 1 + 1 + 1 + 1 + 2 )] x1.085 μs ＝ 1627.5 μs.
Adding the two instructions outside loop we have 1627.5 μs + 3 x 1.085 μs ＝ 1630.755 μs

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Question: 3.2

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