Question 6.9: Examine the following code and analyze the result. MOV A,#+9...
Examine the following code and analyze the result.
| MOV A,#+96 ;A=0110 0000 (A=60H) MOV R1,#+70 ;R1=0100 0110(R1=46H) ADD A,R1 ;A=1010 0110 ;A=A6H=-90,INVALID |
\begin{array}{r c}\begin{matrix} \\ + \\ + \end{matrix} \begin{matrix} +96 \\ +70 \\ \hline 166 \end{matrix} & \begin{matrix} 0110 & 0000 \\ 0100 & 0110 \\ \hline 1010 & 0110 \end{matrix} \begin{matrix} \\ \\ \text{ and } OV =1 \end{matrix} \end{array}
According to the CPU, the result is -90, which is wrong. The CPU sets OV=1 to indicate the overflow
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