Question 1.20: A voltage drop of 4 V appears across a resistor of 100 Ω. Wh...
A voltage drop of 4 V appears across a resistor of 100 Ω. What power is dissipated in the resistor?
Here we use P = V ^2 / R (\text { where } V = 4 V \text { and } R = 100 Ω) .
P = V^2 / R = (4 V × 4 V) / 100 Ω = 0.16 W
Hence the resistor dissipates a power of 0.16 W (or 160 mW).
Related Answered Questions
Question: 1.16
Verified Answer:
R = V / I = 15 V / 0.001 A = 15,000 Ω = 15...
Question: 1.15
Verified Answer:
Here we must use V = I × R and en...
Question: 1.26
Verified Answer:
Now B = Φ /A = (0.8 × 10^{−3}) / (500 × 10...
Question: 1.25
Verified Answer:
From Fig. 1.18, the slope of the graph at any poin...
Question: 1.24
Verified Answer:
Re-arranging the formula B=\Phi /A [/latex...
Question: 1.23
Verified Answer:
Applying the formula B=\mu _0 \ I /2\pi \ ...
Question: 1.22
Verified Answer:
The electric field strength will be given by:
[lat...
Question: 1.21
Verified Answer:
Here we use P = I^2 × R but, to ...
Question: 1.19
Verified Answer:
Here we must use P = I × V (where...
Question: 1.18
Verified Answer:
First we must find the resistance of the wire (as ...