Question 6.4.6: Graphing y = a sin (x - c) Graph y = sin (x - π/2) over a on...

Recall that for any function f, the graph of y = f(x – c) is the graph of y = f(x) shifted right c units if c > 0 and left |c| units if c < 0. Comparing the equation y=\sin \left(x-\frac{\pi}{2}\right) \text { with } y =\sin x, \text { we see that } y=\sin \left(x-\frac{\pi}{2}\right) has the form y=\sin (x-c), \text { where } c=\frac{\pi}{2} . Therefore, the graph of y=\sin \left(x-\frac{\pi}{2}\right) is the graph of y=\sin x \text { shifted right } \frac{\pi}{2} units. See Figure 63.