Question 15.15: Four mass points of mass m move on a circle of radius R. Eac...
Four mass points of mass m move on a circle of radius R. Each mass point is coupled to its two neighboring points by a spring with spring constant k (Fig. 15.22). Find the Lagrangian of the system, and derive the equations of motion of the system. Calculate the eigenfrequencies of the system, and discuss the related eigenvibrations.

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The kinetic energy of the system is given by
T=21mν=1∑4s˙ν2. (15.44)
For small displacements from the equilibrium position, the potential reads
V=21kν=1∑4(sν+1−sν)2, s4+1=s1. (15.45)
We set sν=Rφν , and take the angles φν as generalized coordinates. Then the Lagrangian is
L=T−V=21mR2ν=1∑4φ˙ν2−21kR2ν=1∑4(φν+1−φν)2. (15.46)
From the Lagrange equations
dtd∂φ˙ν∂L=∂φν∂L, (15.47)
we find the equations of motion:
dtd∂φ˙ν∂L=mRφ¨ν=−21kR2[2(φν−φν+1)+2(φν−φν−1)]
=∂φν∂L. (15.48)
For the case of four mass points, we then obtain
φ¨1=mk(φ2−2φ1+φ4),φ¨2=mk(φ3−2φ2+φ1),
φ¨3=mk(φ4−2φ3+φ2),
φ¨4=mk(φ1−2φ4+φ3),
With the ansatz φν=Aνcosωt,φ¨ν=−Aνω2cosωt, we are led to the following linear system of equations:
⎝⎜⎜⎜⎛2mk−ω2−mk0−mk−mk2mk−ω2−mk00−mk2mk−ω2−mk−mk0−mk2mk−ω2⎠⎟⎟⎟⎞⎝⎜⎜⎜⎛A1A2A3A4⎠⎟⎟⎟⎞=0 (15.50)
For the nontrivial solutions, the determinant of the coefficient matrix must vanish. This condition leads to the determining equation for the eigenfrequencies:
(2mk−ω2)2(4mk−ω2)(−ω2)=0. (15.51)
The frequencies are
ω12=0, ω22=4mk, ω32=ω42=2mk. (15.52)
To calculate the related eigenvibrations, we insert these frequencies into the system of equations (15.50).
(1) ω12=0:A1=A2=A3=A4. The system does not vibrate but performs a uniform rotation (Fig. 15.23(a)).
(2) ω22=4k/m:A1=A3=−A2=−A4. Two neighboring mass points perform an out-of-phase vibration (Fig. 15.23(b)).
(c) ω32=ω42=2k/m:A1=A2=−A3=−A4 or A1=A4=−A2=−A3. Two neighboring mass points vibrate in phase (Fig. 15.24(a,b)).

