Question 3.8: Classification of Chemical Bonds Classify each bond as nonpo...

Classification of Chemical Bonds
Classify each bond as nonpolar covalent, polar covalent, or ionic.
(a) \text{O}-\text{H}         (b) \text{N}-\text{H}         (c) \text{Na}-\text{F}         (d) \text{C}-\text{Mg}         (e) \text{C}-\text{S}

Strategy
Using Table 3.5, determine the difference in electronegativity between bonded atoms. Then, use the values given in Table 3.6 to classify the type of bond formed.

Table 3.5 Electronegativity Values of the Elements (Pauling Scale)
 

 

 

 

7A
(17)

 

 

 

 

6A
(16)

 

 

 

 

5A
(15)

 

 

 

 

4A
(14)

 

 

 

 

3A
(13)

 

 

 

 

 

 

 

2B
(12)

 

 

 

 

 

 

 

1B
(11)

 

 

 

 

 

 

 

(10)

 

 

 

 

 

 

 

8B
(9)

 

 

 

 

 

 

 

(8)

 

 

 

 

 

 

 

7B
(7)

 

 

 

 

 

 

 

6B
(6)

 

 

 

 

 

 

 

5B
(5)

 

 

 

 

 

 

 

4B
(4)

 

 

 

 

 

 

 

3B
(3)

 

 

 

 

2A
(2)

 

 

1A
(1)

H
2.1
F
4.0
O
3.5
N
3.0
C
2.5
B
2.0
Be
1.5
Li
1.0
Cl
3.0
S
2.5
P
2.1
Si
1.8
Al
1.5
Mg
1.2
Na
0.9
Br
2.8
Se
2.4
As
2.0
Ge
1.8
Ga
1.6
Zn
1.6
Cu
1.9
Ni
1.8
Co
1.8
Fe
1.8
Mn
1.5
Cr
1.6
V
1.6
Ti
1.5
Sc
1.3
Ca
1.0
K
0.8
I
2.5
Te
2.1
Sb
1.9
Sn
1.8
In
1.7
Cd
1.7
Ag
1.9
Pd
2.2
Rh
2.2
Ru
2.2
Tc
1.9
Mo
1.8
Nb
1.6
Zr
1.4
Y
1.2
Sr
1.0
Rb
0.8
At
2.2
Po
2.0
Bi
1.9
Pb
1.8
Tl
1.8
Hg
1.9
Au
2.4
Pt
2.2
Ir
2.2
Os
2.2
Re
1.9
W
1.7
Ta
1.5
Hf
1.3
La
1.1
Ba
0.9
Cs
0.7
Table 3.6 Classification of Chemical Bonds
Most Likely Formed Between Type of Bond Electronegativity Difference Between Bonded Atoms
Two nonmetals or a nonmetal and a metalloid \left.\overset{\text{Nonpolar covalent}}{\underset{\text{Polar covalent}}{}} \right\} Less than 0.5 0.5 to 1.9
A metal and a nonmetal Ionic Greater than 1.9
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Type of Bond Difference in Electronegativity Bond
Polar covalent 3.5 – 2.1 = 1.4 (a) \text{O}-\text{H}
Polar covalent 3.0 – 2.1 = 0.9 (b) \text{N}-\text{H}
Ionic 4.0 – 0.9 = 3.1 (c) \text{Na}-\text{F}
Polar covalent 2.5 – 1.2 = 1.3 (d) \text{C}-\text{Mg}
Nonpolar covalent 2.5 – 2.5 = 0.0 (e) \text{C}-\text{S}

Quick Check 3.8
Classify each bond as nonpolar covalent, polar covalent, or ionic.
(a) \text{S}-\text{H}         (b) \text{P}-\text{H}         (c) \text{C}-\text{F}         (d) \text{C}-\text{Cl}

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