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Question 7.C-L.7: Use Equation 7.9 and describe how to prepare 500 mL of a 0.2...

Use Equation 7.9 and describe how to prepare 500 mL of a 0.250 M NaOH solution from a 6.00 M NaOH solution.

(C_c) ( V_c) = (C_d) (V_d )     (7.9)

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Equation 7.9 is used to calculate the volume of 6.00 M NaOH solution needed.

(C_c) ( V_c) = (C_d) (V_d )\\ \\ (6.00  M) ( V_c) = (0.250  M) (500  mL )\\ \\ V_c = \frac{(0.250  \cancel{ M}) (500  mL )}{(6.00  \cancel{ M})} =  20.8   mL

The solution is prepared by putting 20.8 mL of 6.00 M NaOH solution into a 500-mL flask, adding pure water to
the mark, and making certain the resulting solution is well mixed.

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