Question 6.6: If 5.00 g glucose are dissolved in 1.00 × 10² mL of solution...
If 5.00 g glucose are dissolved in 1.00 × 10² mL of solution, calculate the molarity, M, of the glucose solution.
Step 1. To use our expression for molarity it is necessary to convert from units of grams of glucose to moles of glucose. The molar mass of glucose is 1.80 × 10² g/mol. Therefore
5.00 \cancel{g} \times \frac{1 mol}{1.80 \times 10^2 \cancel{g}} = 2.78 \times 10^{-2} mol glucoseStep 2. We must convert mL to L:
1.00 \times 10^2 \cancel{mL} \times \frac{1 L}{ 10^3 \cancel{mL}} = 1.00 \times 10^{-1} LStep 3. Substituting these quantities:
M_{glucose}= \frac{2.78 \times 10^{-2} mol}{1.00 \times 10^{-1} L} \\ = 2.78 \times 10^{-1} MRelated Answered Questions
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