Question 6.10: Calculate the number of equivalents per liter (eq/L) of phos...
Calculate the number of equivalents per liter (eq/L) of phosphate ion, PO_4 ^{3–}, in a solution that is 5.0 \times 10^{–3} M phosphate.
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Step 1. It is necessary to use two conversion factors:
mol PO_4 ^{3–} → mol charge
and
mol charge → eq PO_4 ^{3–}
Step 2. Arranging these factors in sequence yields:
\frac{5.0 \times 10^{-3} \cancel{mol PO_4 ^{3–}}}{1 L} \times \frac{3 \cancel{mol charge}}{1 \cancel{mol PO_4 ^{3–}}} \times \frac{1 eq PO_4 ^{3–}}{1 \cancel{mol charge}} = \frac{1.5 \times 10^{-2} eq PO_4 ^{3–}}{L}
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