Question 4.T.8: (Root Test) Given a series ∑xn, let r = lim sup ^n√|xn|. The...
(Root Test)
Given a series ∑xn, let
r=limsupn∣xn∣.Then
(i) ∑xn is absolutely convergent if r < 1.
(ii) ∑xn is divergent if r > 1.
(iii) The test is inconclusive if r = 1.
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(i) If r < 1, choose a positive number c ∈ (r, 1). Let ε = c − r. By Theorem 3.16(i), there is a positive integer N such that
n ≥ N ⇒ n∣xn∣<r+ε=c
⇒ ∣xn∣<cn.
Since the geometric series ∑cn converges, ∑∣xn∣ by comparison, and therefore ∑xn is absolutely convergent.
(ii) By Theorem 3.16(iv), there is a subsequence (xnk) of (xn) such that
nk∣xnk∣→r.
Since r > 1 there is a positive integer N such that
k ≥ N ⇒ nk∣xnk∣ >1
⇒ ∣xnk∣>1,
and we conclude that the condition xn→0, which is a necessary condition for convergence, is not satisfied.
(iii) In Example 4.3 we found that ∑1/n was divergent, and in Example 4.7 we established the convergence of ∑1/n2. But in both cases r=limn1/np=1.