A gas in a flexible container has a volume of 0.50 L and a pressure of 1.0 atm at 393 K. When the gas is heated to 500. K, its volume expands to 3.0 L. What is the new pressure of the gas in the flexible container?

Strategy
We identify the known quantities and then solve the combined gas law for the new pressure.

Question

A gas in a flexible container has a volume of 0.50 L and a pressure of 1.0 atm at 393 K. When the gas is heated to 500. K, its volume expands to 3.0 L. What is the new pressure of the gas in the flexible container?

Strategy
We identify the known quantities and then solve the combined gas law for the new pressure.

Accepted Answer

Solution
Step 1: The known quantities are:
Initial: [latex]P_1[/latex] = 1.0 atm [latex]V_1[/latex] = 0.50 L [latex]T_1[/latex] = 393 K
Final: [latex]P_2[/latex] = ? [latex]V_2[/latex] = 3.0 L [latex]T_2[/latex] = 500. K
Step 2: Solving the combined gas law for [latex]P_2[/latex], we find:

[latex]P_2 = \frac{P_1V_1T_2}{T_1V_2}= \frac{(1.0 atm) (0.50 \cancel{L})(500. \cancel{K})}{(3.0 \cancel{L}) (393 \cancel{K})}= 0.21 [/latex]

Question 5.3: A gas in a flexible container has a volume of 0.50 L and a p...

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