Question 1.2: David walks east for 6 s at 2 ms^-1 then west for 2s at 1 ms...

David walks east for 6 s at 2 ms^{-1} then west for 2s at 1 ms^{-1}. Draw

i) a diagram of the journey
ii) the speed–time graph
iii) the velocity–time graph.

Interpret the area under each graph.

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i) David’s journey is illustrated below. (Figure 1.19)

ii) Speed–time graph   (Figure 1.20)

iii) Velocity–time graph   (Figure 1.21 )

The area between a velocity time graph and the x axis represents the change in position, that is the displacement.

When the velocity is negative, the area is below the axis and represents a displacement in the negative direction, west in this case.

fig 1.19
fig 1.20
fig 1.21

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