Question 1.2: David walks east for 6 s at 2 ms^-1 then west for 2s at 1 ms...
David walks east for 6 s at 2 ms^{-1} then west for 2s at 1 ms^{-1}. Draw
i) a diagram of the journey
ii) the speed–time graph
iii) the velocity–time graph.
Interpret the area under each graph.
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i) David’s journey is illustrated below. (Figure 1.19)
ii) Speed–time graph (Figure 1.20)
iii) Velocity–time graph (Figure 1.21 )
The area between a velocity time graph and the x axis represents the change in position, that is the displacement.
When the velocity is negative, the area is below the axis and represents a displacement in the negative direction, west in this case.



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